Answer:
4x²-20x+25<0
b²-4ac = (-20)²-4(4*25)=0
Δ =0; one solution : -b/2a = 40/8 =5/2
the inequality is true for all x ∈∅
a²+4a-21<0
b²-4ac = (4)²-4(1*-21)=100
Δ=100;
(-b-√Δ)/2a =(-4-10)/2= -7
(-b+√Δ)/2a=(-4+10)/2 =3
The inequality is there fore true for all a in ]-7;3[`