Answer:

Step-by-step explanation:
We've been given the following information:
- pH of the solution (pH = 2.960)
- the concentration of ethanoic acid (0.100 mol/L).
We need to find out the percentage of the total ethanoic acid and ethanoate concentration that consists of unionized ethanoic acid.
1. Calculate [H+] Concentration
The pH of a solution can be calculated using the formula:
![\LARGE \boxed{\texttt{pH = -log[H+]}}}](https://img.qammunity.org/2024/formulas/chemistry/high-school/oczscs9bgqiocpljzz5iuzb3funvfln05g.png)
❖ [H+] is the concentration of H+ ions in mol/L.
Given the pH of 2.960, we can calculate [H+]:
![\large \boxed{\tt{[H+] = 10^(-pH)}}](https://img.qammunity.org/2024/formulas/chemistry/high-school/oq6dyyggg0mcpb38ubca6cb3scg02wapzz.png)
2. Determine Concentration of Unionized Ethanoic Acid
Unionized ethanoic acid does not dissociate into H+ ions. Therefore, its concentration is the same as concentration of ethanoic acid, which is 0.100 mol/L.
3. Calculate Total Concentration
Now, we calculate the total concentration, which includes both ethanoic acid and ethanoate ions:

4. Find Percentage of Unionized Ethanoic Acid
To find the percentage of unionized ethanoic acid, we divide the concentration of ethanoic acid by the total concentration and multiply by 100:

5. Final Answer
The percentage of the total ethanoic acid and ethanoate concentration that consists of unionized ethanoic acid is approximately 98.9%, which is option A.
#BTH1
________________________________________________________