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Are the lines parallel? Y=-3+2 and 3x+y=6

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Hi there! I'll help you solve this problem!

In order for two lines to be parallel, their slopes should be equal.

We have two lines:


\begin{cases}\sf{y=-3x+2}\\\sf{3x+y=6}}\end{cases}}

Let's convert the second equation to slope-intercept (y = mx + b) form.

To do it, move 3x to the other side, using the opposite operation:


  • \sf{y=6-3x}

  • \sf{y=-3x+6}

Now the lines are:


\begin{cases}\sf{y=-3x+2}\\\sf{y=-3x+6}\end{cases}

Both lines have a slope of -3. which means their slope is the same.

Therefore, they are parallel.

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Best wishes!

User Skunkwerk
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