Question

A line has a slope of ( – 3, 5) and passes through the point (15, – 3). Write its equation in slope-intercept form.

Answer 1

y= -3/5x + 6

Explanation:

When you add the slope, you get this equation. y= -3/5x+b

Now you substitute the y and x coordinate. you get -3 = -3/5(15) + b

Here you get -3 = -9 + b

Now you solve for b getting b =6

So the equation is y= -3/5x + 6

Answer 2

Explanation:

To write the equation of a line in slope-intercept form (y = mx + b), where "m" is the slope and "b" is the y-intercept, you can use the given slope (-3) and the point it passes through (15, -3).

We can start with the point-slope form of the equation:

y - y1 = m(x - x1)

Where (x1, y1) is the given point (15, -3) and "m" is the slope (-3).

y - (-3) = -3(x - 15)

Now, simplify this equation:

y + 3 = -3(x - 15)

y + 3 = -3x + 45

Now, isolate "y" by subtracting 3 from both sides:

y = -3x + 45 - 3

y = -3x + 42

So, the equation of the line in slope-intercept form is:

y = -3x + 42

solved by "MG"