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3. For the homecoming game, tickets had to be sold in advance. The athletic director want

know how many tickets were sold to each of the underclassmen. Here is what they know.
325 more juniors were at the game than freshmen
They sold 200 more ticket to sophomores than freshmen
They sold 125 more tickets to juniors than sophomores
They sold a total of 3,300 tickets
How many juniors bought tickets to the homecoming game?


Help please

3. For the homecoming game, tickets had to be sold in advance. The athletic director-example-1
User Ekawas
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1 Answer

3 votes

Answer:

Let's use algebra to solve this problem. Let "F" represent the number of tickets sold to freshmen, "S" for sophomores, and "J" for juniors.

We are given the following information:

1. 325 more juniors were at the game than freshmen: J = F + 325

2. They sold 200 more tickets to sophomores than freshmen: S = F + 200

3. They sold 125 more tickets to juniors than sophomores: J = S + 125

4. They sold a total of 3,300 tickets: F + S + J = 3,300

Now, we can use these equations to solve for J:

Substitute the expressions for J and S from equations 1 and 2 into equation 3:

(F + 325) = (F + 200) + 125

Now, solve for F:

F + 325 = F + 325

The F cancels out, which means the value of F doesn't matter in this context. So, we have:

325 = 325

This equation is always true, so there isn't a unique solution for F. It could be any value, but it doesn't affect our ability to find the number of juniors (J) since J = F + 325.

Now, we know that J = F + 325. To find the number of juniors, we need to know the value of F (the number of freshmen tickets sold), which isn't given in the problem. Therefore, we cannot determine the exact number of juniors who bought tickets to the homecoming game without the value of F.

hope this helps you

solved by MG

User Mostafa Berg
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