Question

Classwork for 08-YR-ALGEBRA 2 ADV H 02

Streak
32 12/14
The height of a water balloon that is launched int
the air is given by h(t) = -5t² + 40t + 2. From what
height was the balloon released?

Answer 1

The balloon was released from a height of 2 units.

Step-by-step explanation:

The height of the water balloon at any given time can be determined using the formula h(t) = -5t² + 40t + 2. To find the height from which the balloon was released, we need to find the initial height, which is the value of h(t) when t = 0. Plugging in t = 0 into the equation, we get:

h(0) = -5(0)² + 40(0) + 2

h(0) = 2

Therefore, the balloon was released from a height of 2 units.

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