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What is the equation of the line that passes through (1,-6) and (5,-6)

User Jonalogy
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1 Answer

4 votes

Answer:

y = -6

Explanation:

We're looking for a linear equation in the form y=mx+b, where m is the slope and b is the y-intercept. To solve, we need to calculate the slope and then calculate the y-intercept.

1. Slope

Start by calculating the slope, which needs the rise and run:

Rise (how much it goes up): (-6) - (-6) = 0

The first -6 comes from the y position of the first point (1,-6), and the second -6 comes from the y position of the second point (5,-6).

Run (how much it goes to the side): 1 - 5 = -4

The 1 comes from the x position of the first point (1,-6), and the 5 comes from the x position of the second point (5,-6).

The slope is equal to the rise over the run:

Slope = rise ÷ run = 0 ÷ (-4) = 0

Thus, the slope is 0. So far, our equation looks like y=0x+b, which is equivalent to y=b.

2. y-intercept

To find the y-intercept, we take a point and plug it into out equation. We can take either point, and I'm going to take the first point (1,-6). We plug x=1 and y=-6 into our equation and get:

y=0x+b

-6 = 0(1)+b

-6 = 0+b

-b = b

b = -b

Thus, our y-intercept is -6.

3. Putting it all together

When we put the slope and y-intercept into our equation, we get y=0x-6, or y=-6. We can test this by putting in both points: when x=1, y=-6; and when x=5, y=-6. Therefore, we know we have the right answer.

User Gabor Csardi
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7.5k points