Question

Use the values In9≈ 2.2 and In200≈ 5.3 to find the approximate value of log9 200.

A) log9 200 ≈2.4
B) log9 200≈ 0.42
C) log9 200≈7.5
D) log9 200≈ 11.7

Answer 1

Hi,

Answer A (2.41136815...)

Explanation:

`log_9(200)=(ln(200))/(ln(9)) =(5.3)/(2.2) \approx{2.4090...}`