Answer:
The vertex of a quadratic function in the form y = ax^2 + bx + c can be found using the formula x = -b/2a.
In this case, the equation is y = x^2 + 4x. To find the vertex, we need to identify the values of a and b.
Comparing the given equation to the standard form y = ax^2 + bx + c, we can see that a = 1 and b = 4.
Now, we can substitute these values into the formula x = -b/2a:
x = -(4) / 2(1) = -4/2 = -2
Therefore, the x-coordinate of the vertex is -2.
To find the y-coordinate of the vertex, we substitute the x-coordinate (-2) back into the original equation:
y = (-2)^2 + 4(-2) = 4 - 8 = -4
So, the y-coordinate of the vertex is -4.
Therefore, the vertex of the graph of y = x^2 + 4x is (-2, -4).