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∆ABC transforms to produce ∆A'B'C'. Which transformation did NOT take place? Graph shows 2 circles plotted on a coordinate plane. Circle 1 is plotted in quadrant 1 with centered at A (3, 3). Triangle ABC inscribed in circle 1. Circle 2 is plotted in quadrant 3 with centered at A prime (minus 3, minus 3). A. rotation 180° counterclockwise about the origin B. reflection across the origin C. rotation 180° clockwise about the origin D. reflection across the line y = -x

User Baltazar
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Answer:

D. reflection across the line y = -x.

Explanation:

The transformation that did NOT take place is reflection across the line y = -x.

To see this, we can consider the coordinates of the vertices of triangle ABC. Triangle ABC is inscribed in a circle with center A(3, 3), so the coordinates of its vertices must be within a distance of 3 units of A.

If we reflect triangle ABC across the line y = -x, the coordinates of its vertices will be negated. This means that the new triangle, triangle A'B'C', will be inscribed in a circle with center A'(-3, -3), but its vertices will not be within a distance of 3 units of A'.

For example, if one of the vertices of triangle ABC is (2, 1), then its reflection across the line y = -x will be (-2, -1). This point is not within a distance of 3 units of A'(-3, -3).

In contrast, the other three transformations did take place.

Rotation 180° counterclockwise about the origin: This transformation will map triangle ABC to a triangle with the same vertices, but in the opposite orientation. This is consistent with the graph, which shows triangle A'B'C' as a reflection of triangle ABC across the x-axis.

Reflection across the origin: This transformation will map triangle ABC to a triangle with the same vertices, but in the opposite quadrant. This is consistent with the graph, which shows triangle A'B'C' as a reflection of triangle ABC across the origin.

Rotation 180° clockwise about the origin: This transformation will map triangle ABC to a triangle with the same vertices, but in the opposite orientation. This is consistent with the graph, which shows triangle A'B'C' as a reflection of triangle ABC across the y-axis.

Therefore, the answer is D. reflection across the line y = -x.

User Izora
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