Answer:
D. x+12 ≤ 2(x − 3)
Explanation:
The correct answer is: D. x+12 ≤ 2(x − 3)
We can solve this problem by graphing the inequalities. First, we rewrite the inequalities in terms of y:
x + 12 ≤ 5 - y
y ≤ -x + 17
5 - y ≤ 2(x - 3)
y ≥ 2x - 11
Now, we can graph the inequalities:
[asy]
unitsize(0.5 cm);
draw((-10,0)--(10,0));
draw((0,-10)--(0,10));
draw((-10,-17)--(10,17),Arrow(6));
draw((10,17)--(-10,17),Arrow(6));
draw((10,-11)--(-10,11),Arrow(6));
draw((-10,-11)--(10,-11),Arrow(6));
label("y=−x+17", (10,17), E);
label("y=2x−11", (-10,-11), W);
dot("(−3,5)", (-3,5), NW);
[/asy]
The shaded region represents the solutions to both inequalities. We can see that the only statement that is always true for the solutions in the shaded region is:
x + 12 ≤ 2(x - 3)
Therefore, the correct answer is D.