Answer:
the area of triangle ABC is 33/2 square units.
Explanation:
To find the area of triangle ABC, we can use the following formula:
Area = 1/2 * |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|
where (x1, y1), (x2, y2), and (x3, y3) are the coordinates of the vertices of the triangle.
Substituting the coordinates of vertices A, B, and C, we get:
Area = 1/2 * |(-4)(-1 - 3) + (-5)(3 - 6) + (5)(6 - (-1))|
Area = 1/2 * |33|
Area = 33/2
Therefore, the area of triangle ABC is 33/2 square units.