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Find a polynomial function of degree 3 with real coefficients and zeros of -3, -1, and 4, for which f(-2)=-24

User Tyre
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1 Answer

4 votes

Answer:

The answer is:

f(x) = -4x^3 + 52x + 48

Explanation:

Since the polynomial has zeros at -3, -1, and 4, it can be written in the form:

f(x) = a(x + 3)(x + 1)(x - 4)

where a is a real coefficient.

We are given that f(−2)=−24. Substituting x=−2 into the above equation, we get:

-24 = a(-2 + 3)(-2 + 1)(-2 - 4)

Simplifying both sides, we get a=−4.

Therefore, the polynomial function we are looking for is:

f(x) = -4(x + 3)(x + 1)(x - 4)

This can also be written in standard form as:

f(x) = -4x^3 + 52x + 48

User Kaarto
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