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What is the product of (4+3i)(4-3i)
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What is the product of (4+3i)(4-3i)

User Narendra Motwani
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Answer:


(4+3i)(4-3i)\\=4^2-(3i)^2\\=16-(3^2i^2)\\=16-[9(-1)]\ \ \ [\ i^2=-1\ ]\\=16-(-9)\\=16+9\\=25

User Vardiak
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