Question

Find the mass of 2.15 x 1023 particles of AgCl (silver chloride)

The molar mass of AgCl is 143.32 g/mol

Answer 1

`\huge{ \boxed{51.17 \: g}}`

Step-by-step explanation:

The mass of
`\bold{AgCl}` can be found by using the formula;

mass = number of moles × molar mass

From the question;

molar mass of AgCl = 143.32 g/mol

Since the number of particles was given the number of moles of the compound can be found by using the formula;

`n = (N)/(L)`

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question;

N = 2.15 × 10²³ particles

`\therefore \: n = \frac{2.15 * {10}^(23) }{6.02 * {10}^(23) } \\ = 0.357 \: moles`

The number of moles attained is then substituted into the formula for finding the mass of the compound.

`\therefore \: mass = 0.357 * 143.32 \\ 51.17 \: g`