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Solve the system by substitution. y= 3x−50 ; y= −2x

2 Answers

5 votes

Final answer:

The solution is x = 10 and y = -20.

Step-by-step explanation:

To solve the system by substitution you need to substitute one equation into the other since both are solved for y.

We are given two equations:

  • Equation 1: y = 3x - 50
  • Equation 2: y = -2x

Substitute Equation 2 into Equation 1. This gives us:

  1. -2x = 3x - 50
  2. Add 2x to both sides: 0 = 5x - 50
  3. Add 50 to both sides: 50 = 5x
  4. Divide both sides by 5: x = 10

Now that we have the value of x, substitute it back into either Equation 1 or Equation 2 to find y.

  1. Substitute x into Equation 2: y = -2(10)
  2. Multiply: y = -20

So, the solution to the system is x = 10 and y = -20.

User Kluu
by
7.7k points
6 votes

Answer:

To solve the system of equations by substitution, we can substitute the value of y from one equation into the other equation.

Given the system of equations:

y = 3x - 50 ...(Equation 1)

y = -2x ...(Equation 2)

We can substitute the value of y from Equation 2 into Equation 1:

-2x = 3x - 50

Next, let's solve for x:

-2x - 3x = -50

-5x = -50

x = -50 / -5

x = 10

Now that we have the value of x, we can substitute it back into either of the original equations to find the value of y. Let's substitute it into Equation 2:

y = -2(10)

y = -20

Therefore, the solution to the system of equations is x = 10 and y = -20.

User Dmzkrsk
by
7.3k points