Final answer:
The peak value of the induced emf in the secondary winding of a transformer can be calculated using Faraday's law. However, without knowing the number of turns on the primary winding, the exact value of the secondary induced emf cannot be determined.
Step-by-step explanation:
To determine the peak value of the induced emf in the secondary winding of a single-phase transformer with a turns ratio of 10:1, a primary voltage of 220v, a frequency of 50hz, and a maximum core flux of 0.02 wb, we can use Faraday's law of electromagnetic induction. The formula to calculate the induced emf (E) is given by:
E = N * (dφ/dt). Here, 'N' is the number of turns, φ is the magnetic flux, and (dφ/dt) is the rate of change of the magnetic flux.
Because the flux is sinusoidal and we need the peak value of emf, let's use the peak flux value and the maximum rate of flux change considering it's a sinusoidal change: (dφ/dt)max = 2 * π * f * φmax,
Therefore, the peak emf induced in secondary winding (E2) is:
E2 = N2 * 2 * π * f * φmax,
Given N2 = N1 / 10 (due to the 10:1 turns ratio), f = 50 Hz, and φmax = 0.02 Wb,
E2 = (N1 / 10) * 2 * π * 50 Hz * 0.02 Wb.
However, we do not have the number of primary turns (N1), so without N1, we cannot calculate the exact value of E2. If the question had provided the value of N1, we would proceed to plug in the values and calculate the induced EMF using the above equation.