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Mary went shopping with a sum of money. If she bought 4 blouses, she would be short of $6. If she used the same amount of money to buy 3 blouses and 2 belts, she would be left with $3. Each belt cost $5.​

(a) What was the cost of each blouse?
(b) How much money did Mary have?

User Cosaquee
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1 Answer

4 votes

Answer:

Explanation:

Let's call the amount of money Mary had initially "X" (in dollars).

According to the information given:

If she bought 4 blouses, she would be short of $6. This means that the cost of 4 blouses is $6 more than her initial amount.

So, the cost of 4 blouses is X - 6 dollars.

If she used the same amount of money to buy 3 blouses and 2 belts, she would be left with $3. The total cost of 3 blouses and 2 belts is equal to her initial amount plus $3.

So, 3 times the cost of 1 blouse plus 2 times the cost of 1 belt is equal to X + $3.

Now, we are also given that each belt costs $5. Therefore, the cost of 2 belts is 2 * $5 = $10.

Now we can set up a system of equations based on the information:

4 * Cost of 1 blouse = X - 6

3 * Cost of 1 blouse + 2 * $5 = X + $3

Let's solve this system of equations:

From the first equation, we can express the cost of 1 blouse:

Cost of 1 blouse = (X - 6) / 4

Now, substitute this expression into the second equation:

3 * ((X - 6) / 4) + $10 = X + $3

Now, let's solve for X:

3 * (X - 6) / 4 + $10 = X + $3

Multiply both sides by 4 to get rid of the fraction:

3 * (X - 6) + 40 = 4 * (X + 3)

Now, distribute the 3 on the left side:

3X - 18 + 40 = 4X + 12

Combine like terms:

3X + 22 = 4X + 12

Subtract 3X from both sides:

22 = X + 12

Subtract 12 from both sides:

X = 22 - 12

X = 10

So, Mary initially had $10. Therefore:

The cost of 1 blouse is (X - 6) / 4 = ($10 - $6) / 4 = $4 / 4 = $1.

The cost of 2 belts is 2 * $5 = $10.

Mary had enough money to buy 3 blouses and 2 belts, and she had $3 left, which matches our calculations:

3 * $1 + 2 * $5 = $3 + $10 = $13

So, the given information is consistent, and Mary had $10 to start with.

User Cade Roux
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