The correlation coefficient of the data about time and heart rate is 0.98.
How to calculate correlation coefficient?
We have been given time and heart rates of students in Mrs. Anderson's health class and we have to find the value of correlation coefficient.
The formula by Karl Pearson to calculate correlation coefficient is as under:
Correlation coefficient = ∑(x - x-bar) (y - y-bar))/(√[∑(x - x-bar)²]√[∑(y - y-bar)²]
We have to calculate figures required to fill in the formula which are:
∑(x-x bar)(y-y bar)=350
∑(x - x-bar)² = 44.67
∑(y - y-bar)² = 2872.25
Correlation coefficient=350/(√44.67 * √2872.25)
=350/6.68*53.59
=350/357.98
=0.977
After rounding off to nearest hundred it will be 0.98.
Hence the correlation coefficient of the data about time and heart rate is 0.98.