Question

A man is pushing a 15 kg table using a force of 81 Newtons, but a force of friction 22

opposes the motion of the table.
What is the net force applied to the table? ROUND YOUR ANSWER TO THE NEAREST
INTEGER.

Answer 1

Answer: Fnet= 59 N and a= 3.39 m/s^2

Step-by-step explanation:

Fnet = Fpush + Ffr

Fnet = 81N + -22N

Fnet = 59 N

Fnet = ma

59 N = 15kg a

59N/15kg = 3.9333333333333m/2^2

Rounded to 3.9 m/s^2