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The sum of two numbers is 70. One number is 4 times as large as the other. what are the numbers?

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Answer:

The two numbers are 56 and 14

Explanation:

Let's denote the two numbers as x and y. According to the problem, we have two equations:

1. The sum of the two numbers is 70, so we can write this as: x + y = 70.

2. One number is 4 times as large as the other, so we can write this as: x = 4y.

We can substitute equation 2 into equation 1 to solve for y:

x + y = 70

4y + y = 70

5y = 70

y = 70 / 5

y = 14

Substitute y = 14 into equation 2 to solve for x:

x = 4 * 14

x = 56

So, the two numbers are 56 and 14.

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