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The sum of two numbers is 21.5 times the first number added to 2 times the second number is 66.find the two number

User Kazem
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1 Answer

1 vote

Answer: first number = -3.3846 and second number = 69.3843

Step-by-step explanation: Let the first numbers be x and the second number be y.

x + y = 21.5x + 2y = 66

splitting the above equation into simultaneous equations, we have

x + y = 21.5x + 2y ...........................eqn 1

21.5x + 2y = 66 ...............................eqn 2

from eqn 1, we collect like terms and simplify and we have

21.5x - x +2y -y = 0

20.5x + y = 0 .............................eqn 3

solving eqns 2 and 3 simultaneously

20.5x + y = 0

21.5x + 2y = 66

multiply eqn2 by the coefficient of y in equ 3 and multiply eqn 3 by the coefficient of y in eqn 2, we have

20.5x + y = 0 x 2 ..........................eqn 4

21.5x + 2y = 66 x 1 ...........................eqn 5

41x + 2y = 0 ........................... eqn 6 (result of eqn 4)

21.5x + 2y = 66 .......................eqn 7 (result of equation 5)

subtract eqn 7 from eqn 6, we have

19.5x = -66

x = -66/19.5 = -3.3846

substituting x into eqn 3 we have

20.5 * (-3.3846) + y = 0

-69.3843 + y = 0

When a number crosses the equality sign, the sign on it changes, therefore we will have

y = 66.3843

Hence, the two numbers are -3.3846 and 66.3843

User Ikhsan Assaat
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