Question

A triangle has vertices on a coordinate grid at P(4, -9), Q(-1, -9), and R(4,6).What is the length, in units, of PQ?

Answer 1

Given:

The coordinates of point P, (x1, y1)=(4, -9).

The coordinates of point Q, (x2, y2)=(-1, -9).

The length of PQ can be calculated as,

`\begin{gathered} PQ=\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ PQ=\sqrt[]{(-1-4)^2+(-9-(-9))^2} \\ PQ=\sqrt[]{(-5)^2+0} \\ PQ=\sqrt[]{5^2} \\ PQ=5 \end{gathered}`

Therefore, the length PQ