Question

Teresa buys candy that costs$6 per pound. She will spend less than $66 on candy. What are the possible numbers of pounds she will buy? Use p for the number of pounds Teresa will buy. Write your answer as an inequality solved forp .

Answer 1

To determine the possible number of pounds (p) that Teresa can buy, given that she will spend less than $66 on candy at a rate of $6 per pound, you can set up the following inequality:

Total cost of candy (6p) must be less than $66.

Mathematically, this can be expressed as:

6p < 66

Now, you can solve for p by dividing both sides of the inequality by 6:

(6p) / 6 < 66 / 6

This simplifies to:

p < 11

So, Teresa can buy a maximum of 10 pounds (p) of candy if she wants to spend less than $66. This is because if she bought 11 pounds, it would cost her 11 pounds * $6/pound = $66, which is equal to her spending limit, not less than it.

Therefore, the inequality solved for p is:

p < 11

Answer 2

Answer: p < 11

Explanation:

Let p be the number of pounds of candy that she buys. We know that the cost per pound is 6 dollars and that she will spend less than 66 dollars.

$6p < $66

Divide both sides of the inequality by $6 to solve for p:

p < 11