Question

The net force acting on a 12.6-kg object is given by Fx = (20 - x) N, where Fx is in

newtons and x is in meters. How much work is done on the object as it moves from x
= 0 to x = 10 m?

Answer 1

The work done on the object as it moves from x = 0 to x = 10 m is 50 Joules.

Step-by-step explanation:

The work done on an object is given by the formula:

W = ∫ F dx

Where W is the work done, F is the force, and dx is the displacement.

In this case, the force is given by Fx = (20 - x) N. We need to calculate the work done as the object moves from x = 0 to x = 10 m.

To calculate the work done, we integrate the force with respect to x:

W = ∫ (20 - x) dx

W = ∫ 20 dx - ∫ x dx

W = 20x - (1/2)x^2

Substituting x = 10 and x = 0 into the equation, we get:

W = 20(10) - (1/2)(10)^2

W = 100 - 50

W = 50 J

Therefore, the work done on the object as it moves from x = 0 to x = 10 m is 50 Joules.

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