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11 votes
11 votes
.A jar contains 15 green marbles numbered 1 through 15 and 9 red marbles numbered 1 through 9. A marble isdrawn at random from the jar. Find the probability that the marble is green or even numbered.

User Phillip Mills
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1 Answer

5 votes
5 votes

Answer: 19/24

Step-by-step explanation:

From the information given,

Number of green marbles = 15

Number of red marbles = 9

Total number of marbles = 15 + 9 = 24

Probability is expressed as

number of favorable outcomes/number of total outcomes

Probability f selecting a greeen marble = 15/24

Even numbers divide 2 without a remainder. The even numbered marbles are

red = 2, 4, 6, 8

green = 2, 4, , 68, 10, 12, 14

Total number of even numbered marbles = 11

Probability of selecing an oevennumber = 10124

The events are not mutually exclusive becuse they can occur together. For two ebvents, A and B that are not mutually exclusive,

P(A U B) = P(A) + P(B) - P(A and B)

Thus,

the probability that the marble is green or even numbered = Probability of selecting a green marble + Probability of selecting an even number - Probability of selecting a green and even numbered marble

Number of green even numbere marble s = 7

Probability of selecting a green and even numbered marble = 7/24

Thus,

the probability that the marble is green or even numbered = 15/24 + 11/24 - 7/24

the probability that the marble is green or even numbered = 19/24

User Foxanna
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