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Suppose a new element has been made. Chemical tests show it is an alkaline earth metal. a) Predict how many electrons will be in the valence shell b) Predict the ionic charge of the ion that is element forms.

User Athos
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Alkaline earth metals are the elements that make up group 2 of the Periodic Table. Like Be, Mg, Ca, Sr, Ba and Ra.

a) Let's do the electronic distribution of two elements of group 2:

Mg atomic number is 12

Ca atomic number is 20

Eletronic distribution:

Mg - 1s² 2s² 2p⁶ 3s²

Ca - 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²

Valence shell is marked on the electronic distribution. It means that both have 2 electrons in the valence shell.

b) To predict the ionic charge of the ion, we need to lose or gain electrons in order to obtain 8 electrons in the valence shell. So for alkaline earth metals, they need to lose 2 electrons in order to obtain 8 electrons in the valence shell:

Mg - 1s² 2s² 2p⁶ 3s²

Loses 2 electrons:

Mg²⁺ - 1s² 2s² 2p⁶ - 8 electrons in the valence shell

So, the ionic charge of the ion that alkaline earth metals form is 2+.

User Psykeron
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