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A Girl walks 5km due north then 10 km in the direction OF 60 degree North OF East toward her Final destination Find the resultant displacement​

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Answer:

The resultant displacement is 5√2 kilometers.

Step-by-step explanation:

To find the resultant displacement, we can use vector addition. The girl's movement can be represented as two vectors: one going north (5 km) and the other going in the direction of 60 degrees north of east (10 km).

The 5 km north can be represented as a vector in the north direction (0 degrees). So, it has a northward component of 5 km and no eastward component.

The 10 km at 60 degrees north of east can be split into two components: one in the north direction and one in the east direction. To find these components, we can use trigonometry.

The northward component = 10 km * sin(60 degrees) = 10 km * (√3/2) = 5√3 km

The eastward component = 10 km * cos(60 degrees) = 10 km * (1/2) = 5 km

Now, we have two components:

Northward component: 5 km

Eastward component: 5 km (from the 10 km at 60 degrees north of east) + 0 km (from the 5 km due north)

To find the resultant displacement, we can use the Pythagorean theorem because these two components form a right triangle:

Resultant displacement = √(Northward component^2 + Eastward component^2)

Resultant displacement = √(5^2 + 5^2)

Resultant displacement = √(25 + 25)

Resultant displacement = √50

Resultant displacement = 5√2 km

So, the resultant displacement is 5√2 kilometers

User Nastya Gorban
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