Question

5. A farmer waters his crops with a pivot sprinkler. This sprinkler rotates and spreads water in a circle with a of radius 224 m. What is the total area that can be watered by this sprinkler? Round your answer to the nearest whole number.​

Answer 1

• 157, 552 m²

Explanation:

We are given ,

A farmer waters his crops with a pivot sprinkler. This sprinkler rotates and spreads water in a circle with a of radius 224 m.

To calculate the the total area that can be watered by this sprinkler we can simply use to area formula. since we have been given of the Circle so we can use the formula,

 
`\sf Area \: of \: circle = \pi r^2`

where, value of
`\pi` is approximately 3.14 and r is the radius.

Plugging the required values, we have

 
`\sf Area = 3.14 * ( 224 )^2`

 
`\sf Area = 3.14 * 50176`

 
`\sf Area \approx 157, 552.6`

Nearest whole number,

`\sf Area \approx 157, 552`

Therefore, the total area that can be watered by this sprinkler is 157, 552 m²