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Given that f(y)=y^2/3+1.calculate the value of Y when F(y)=4

User Kidroca
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1 Answer

2 votes

Answer:

y = 3√3

Explanation:

we can subtract 1 from both sides

y^2/3 + 1 = 4

y^2/3 = 3

to get rid of the exponent, we can raise both sides to the power of 3/2:

y^2/3 = 3

y = 3^3/2

from here, we can use algebra to find the answer:

y = sqrt(27)

y = 3√3

User Carmina
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7.8k points