Question

A brick is 10cm long, 5 cm wide and 5 cm thick. It weighs 25 N and is lying on the ground. Find the

pressure exerted by the brick on the ground?

Answer 1

5000 Pa

Step-by-step explanation:

• To find the pressure exerted by the brick on the ground, you can use the formula:

`\[ \text{Pressure} = \frac{\text{Force}}{\text{Area}} \]`

• In this case, the force is the weight of the brick, which is 25 N. To calculate the area, you can use the formula for the area of the bottom surface of the brick, which is length multiplied by width:

`\[ \text{Area} = \text{length} * \text{width} \]`

`\[ \text{Area} = 10 \, \text{cm} * 5 \, \text{cm} \]`

`\[ \text{Area} = 50 \, \text{cm}^2 \]`

• Now, you need to convert the area from square centimeters to square meters because the pressure formula requires the area to be in square meters.
• There are
  `\( 100 \, \text{cm} * 100 \, \text{cm} = 10000 \, \text{cm}^2 \) in \( 1 \, \text{m}^2 \)`.
• So, the area in square meters is:

`\[ \text{Area in square meters} = \frac{50 \, \text{cm}^2}{10000 \, \text{cm}^2/\text{m}^2} \]`

`\[ \text{Area in square meters} = 0.005 \, \text{m}^2 \]`

• Now, you can calculate the pressure using the formula:

`\[ \text{Pressure} = \frac{25 \, \text{N}}{0.005 \, \text{m}^2} \]`

`\[ \text{Pressure} = 5000 \, \text{N/m}^2 \]`

• Therefore, the pressure exerted by the brick on the ground is
  `\( 5000 \, \text{N/m}^2 \) or \( 5000 \, \text{Pa} \) (Pascal).`