Question

Iron(III) oxide reacts with carbon to give iron and carbon monoxide, as shown below.

Fe₂O3 (s) + C (s) → Fe (s) + CO (g)
How many grams of C (s) are required to react with 27.28 g of Fe₂O3? Round your answer to three
decimal places.

Answer 1

12.5573 grams of C (s) are required to react with 27.28 g of Fe₂O₃.

Step-by-step explanation:

Let's start by writing the balanced chemical equation for the reaction:

Fe₂O₃ (s) + 3C (s) → 2Fe (s) + 3CO (g)

From the balanced equation, we can see that 1 mole of Fe₂O₃ reacts with 3 moles of C.

First, we need to determine the number of moles of Fe₂O₃:

moles of Fe₂O₃ = mass / molar mass

moles of Fe₂O₃ = 27.28 g / (55.845 g/mol + 16 g/mol x 3) = 0.3487 mol

Now, we use the molar ratio between Fe₂O₃ and C to find the number of moles of C:

moles of C = moles of Fe₂O₃ x (3 moles C / 1 mole Fe₂O₃)

moles of C = 0.3487 mol x 3 = 1.0461 mol

Finally, we can calculate the mass of C required using its molar mass:

mass of C = moles of C x molar mass of C

mass of C = 1.0461 mol x 12.01 g/mol = 12.5573 g