Answer:
8
Explanation:
Find the smaller of 2 consecutive integers, x, if the sum of the smaller and 4 times the larger is 44.
Two consecutive integers are represented as:
Smaller integer = x ,
Larger Integer = x + 1
If the sum of the smaller and 4 times the larger is 44
x + 4(x + 1) = 44
x + 4x + 4 = 44
5x + 4 = 44
5x = 44 - 4
5x = 40
x = 40/5
x = 8
Therefore, the smaller of 2 consecutive integers which is x = 8