Question

How much energy is needed to convert 64.09 grams of water at 100.°C to steam at 128.40 °C? specific heat (steam) = 2.09 J/g°C specific heat (water) = 4.18 J/g°C heat of fusion = 6.02 kJ/mol heat of vaporization = 40.6 kJ/mol

Answer 1

Energy needed to convert the whole mass of liquid phase water to.gas phase water

E = 64.09 g × 4.18 = 267.89 J

delta T = 128.4-100 = 28.4 deg

total energy needed= 28.4× 64.09 + 267.89 + 2.09× 64.09 of.saturated steam to superheated

= 1820.16+ 267.89+ 133.95

= 2221.9 J