Question

(a) What is the maximum mass of iron, in grams, that can be obtained from 454 g (1.00 lb) of

iron(III) oxide?

Answer 1

To calculate the maximum mass of iron that can be obtained from iron(III) oxide, you need to consider the balanced chemical equation for the reaction and use the molar masses of the compounds involved.

Step-by-step explanation:

To find the maximum mass of iron that can be obtained from iron(III) oxide, you need to consider the balanced chemical equation for the reaction between iron(III) oxide and carbon monoxide:

Fe2O3 + 3CO → 2Fe + 3CO2

From the balanced equation, you can see that 1 mole of iron(III) oxide reacts with 3 moles of carbon monoxide to produce 2 moles of iron. The molar mass of iron(III) oxide is 159.69 g/mol. To calculate the maximum mass of iron, you need to determine the moles of iron(III) oxide and then convert it to grams:

1. Calculate the moles of iron(III) oxide: 454 g ÷ 159.69 g/mol = 2.84 mol
2. Calculate the moles of iron: 2.84 mol × (2 moles of iron / 1 mole of iron(III) oxide) = 5.68 mol
3. Convert moles of iron to grams: 5.68 mol × 55.85 g/mol = 317 g

Therefore, the maximum mass of iron that can be obtained from 454 g of iron(III) oxide is 317 grams.

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