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A function is defined using the formula y=1/3x+5. If the domain of the function is [-12,9,18], then which of the following is not a element of the function's range?

2 Answers

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To determine which value is not an element of the function's range, we first need to find the range of the function defined by the formula y = (1/3)x + 5. The range is the set of all possible values of y for the given domain.

The domain you provided is [-12, 9, 18]. However, this domain does not seem to be written correctly. A domain is typically given as a range of values, and it should not include commas. I will assume you meant the domain to be [-12, 9, 18] as separate values. In that case, we can calculate the corresponding range.

For each value in the domain, calculate the corresponding y value using the formula:

When x = -12:

y = (1/3)(-12) + 5 = -4 + 5 = 1

When x = 9:

y = (1/3)(9) + 5 = 3 + 5 = 8

When x = 18:

y = (1/3)(18) + 5 = 6 + 5 = 11

So, the range of the function for the given domain is {1, 8, 11}.

Now, to determine which value is not an element of the range, we can compare it to the range values:

3 is not an element of the range {1, 8, 11}, so 3 is not in the range of the function.

Therefore, 3 is the value that is not an element of the function's range.

User Raffaella
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6 votes

Answer:

So, the range of the function for the given domain [-12,9,18] is [1,8,11]. Any number not in this set is not an element of the function’s range.

Explanation:

The function is defined as :


y= (1)/(3)x +5

To find the range of the function for the given domain, we substitute each value from the domain into the function:

  • For x = -12, y =


(1)/(3)* (-12) +5=-4+5=1

  • For x = 9, y =


(1)/(3) * 9 +5= 3+5 =8

  • For x = 18, y =


(1)/(3) * 18 +5 = 6 +5= 11

So, the range of the function for the given domain [-12,9,18] is [1,8,11]. Any number not in this set is not an element of the function’s range.

User Laily
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8.4k points