Answer:
False , there is one solution
Explanation:
given the system of equations
3x + 5y = 20 → (1)
- 2x + 5y = 20 → (2)
subtract (2) from (1) term by term
3x - (- 2x) + (5y - 5y = 20 - 20
3x + 2x + 0 = 0
5x = 0 ⇒ x = 0
substitute x = 0 into either of the 2 equations and solve for y
substituting into (1)
3(0) + 5y = 20
0 + 5y = 20
5y = 20 ( divide both sides by 5 )
y = 4
solution is (0, 4 )