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Solve the equation and then check for extraneous solutions. 4|3x+4|=4x+8

User Fhoxh
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Answer:

Explanation:

To solve the equation 4|3x+4|=4x+8, we need to eliminate the absolute value and solve for x. Let's break it down step-by-step:

Step 1: Remove the absolute value symbols by considering two cases:

Case 1: 3x + 4 ≥ 0

In this case, the absolute value of 3x + 4 remains as is: 4|3x+4| = 4(3x + 4)

Case 2: 3x + 4 < 0

In this case, the absolute value of 3x + 4 becomes its negation: 4|3x+4| = 4(-(3x + 4))

Step 2: Simplify the equations:

Case 1: 4(3x + 4) = 4x + 8

Simplify the equation: 12x + 16 = 4x + 8

Combine like terms: 12x - 4x = 8 - 16

Simplify further: 8x = -8

Divide both sides by 8: x = -1

Case 2: 4(-(3x + 4)) = 4x + 8

Simplify the equation: -12x - 16 = 4x + 8

Combine like terms: -12x - 4x = 8 + 16

Simplify further: -16x = 24

Divide both sides by -16: x = -1.5

Step 3: Check for extraneous solutions by substituting the obtained values back into the original equation.

For x = -1:

4|3(-1)+4| = 4(-1) + 8

4|1| = -4 + 8

4(1) = 4

4 = 4 (True)

For x = -1.5:

4|3(-1.5)+4| = 4(-1.5) + 8

4|0.5| = -6 + 8

4(0.5) = 2

2 = 2 (True)

Since both values satisfy the original equation, there are no extraneous solutions.

Therefore, the solutions to the equation 4|3x+4|=4x+8 are x = -1 and x = -1.5.

User Harrington
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