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Given that one root of the quadratic equation 2x2+ax+3=02x2+ax+3=0 is 1, what is the value of aa? A) 2 B) 3 C) -1 D) -3

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To find the value of a, we'll use the quadratic formula to solve for the roots. The quadratic formula is as follows:

x = [-b ± sqrt(b^2 - 4ac)] / 2a

However, we know one root of the equation is 1, so we can substitute this into the equation to solve for 'a':

1 = [-a ± sqrt(a^2 - 4*2*3)] / 2*2

This simplifies further to:

1 = [-a ± sqrt(a^2 - 24)] / 4

To rearrange the equation and isolate 'a', we multiply both sides by 4:

4 = -a ± sqrt(a^2 - 24)

Subtract 4 from both sides:

a = -4 ± sqrt(16 - 24)

This results in the solutions:

a = -4 +/- sqrt(-8)

However, the square root of -8 is not a real number. We can conclude that there has been a mistake in the equation or the statement of the problem.

As such, none of the provided options (A) 2, B) 3, C) -1, or D) -3 can be the correct answer.

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