Question

A hockey puck of mass 0.50 kg is traveling at 10m / s on a horizontal surface slows to 2.0 m / s over a distance of 80 m. Determine the frictional force acting on the puck and the coefficient of kinetic friction between the puck and the surface. PLEASE HELP

Answer 1

Frictional force = 0.3N

from; V²= U²+ 2as

v=2m/s

u=10m/s

s=80m

a=??

a=(v²-u²)/2s

a=(2²-10²)/2(80)

a=-0.6m/s²

Force = mass × acceleration

= 0.5×-0.6

= -0.3N

But the frictional force is opposite direction to the applied force

hence =0.3N