Question

When 31 g of copper(II) carbonate is used, how many grams of carbon dioxide form? (Provide the chemical equation)

Answer 1

The chemical equation for the reaction is 2CuCO3(s) => 2CuO(s) + 2CO2(g) + O2(g). To determine the grams of carbon dioxide formed when 31 g of copper(II) carbonate is used, the molar mass of copper(II) carbonate is calculated, then the moles of copper(II) carbonate are determined, and finally, the moles of carbon dioxide are converted to grams using the molar mass.

Step-by-step explanation:

The chemical equation for the reaction of copper(II) carbonate to form carbon dioxide is: 2CuCO3(s) → 2CuO(s) + 2CO2(g) + O2(g). From the balanced equation, we can see that for every 2 moles of copper(II) carbonate, 2 moles of carbon dioxide are produced.

So, if 31 g of copper(II) carbonate is used, the amount of carbon dioxide formed can be calculated using the molar mass of copper(II) carbonate and the molar ratio of carbon dioxide to copper(II) carbonate:

1. Calculate the molar mass of copper(II) carbonate (CuCO3)
2. Convert the given mass of copper(II) carbonate to moles using the molar mass
3. Use the molar ratio from the balanced equation to calculate the moles of carbon dioxide produced
4. Convert the moles of carbon dioxide to grams using the molar mass of carbon dioxide. By following these steps, you can determine the grams of carbon dioxide formed when 31 g of copper(II) carbonate is used.

Learn more about Copper(II) carbonate and carbon dioxide formation