Answer:
To determine the number of grams of oxygen in 5875 grams of sugar, we need to know the chemical composition of sugar. Common table sugar, or sucrose (C12H22O11), consists of carbon (C), hydrogen (H), and oxygen (O) atoms.
The molar mass of sucrose is calculated as follows:
Carbon (C) has a molar mass of approximately 12.01 g/mol.
Hydrogen (H) has a molar mass of approximately 1.01 g/mol.
Oxygen (O) has a molar mass of approximately 16.00 g/mol.
The molar mass of sucrose (C12H22O11) is the sum of the molar masses of its constituent elements:
Molar mass of C12H22O11 = (12.01 g/mol × 12) + (1.01 g/mol × 22) + (16.00 g/mol × 11)
Molar mass of C12H22O11 ≈ 342.34 g/mol
Now, you have 5875 grams of sugar, and you want to find out how many grams of oxygen are in this amount. To do that, we'll determine the proportion of oxygen in sucrose.
The proportion of oxygen in sucrose is:
(Oxygen's molar mass / Molar mass of C12H22O11) = (16.00 g/mol / 342.34 g/mol)
Now, we can use this proportion to calculate the grams of oxygen in 5875 grams of sugar:
Grams of oxygen = (Proportion of oxygen) × (5875 grams)
Grams of oxygen = (16.00 g/mol / 342.34 g/mol) × 5875 grams ≈ 275.89 grams
So, there are approximately 275.89 grams of oxygen in 5875 grams of sugar.
Step-by-step explanation: