Question

An equation of a line in point slope form that passes through the points (-8,-3) and has a slope of 1/2

Answer 1

`(\stackrel{x_1}{-8}~,~\stackrel{y_1}{-3})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{2} \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{(-8)}) \implies y +3 = \cfrac{1}{2} ( x +8) \\\\\\ y+3=\cfrac{1}{2}x+4\implies {\Large \begin{array}{llll} y=\cfrac{1}{2}x+1 \end{array}}`