Final answer:
The instantaneous acceleration is equal to 0 near the time t = 1.0 s.
Step-by-step explanation:
To find the time at which the instantaneous acceleration is equal to 0, we need to determine when the particle's acceleration is equal to 0. In this case, the acceleration is given by the second derivative of the position function.
The position function is given as r(t) = (3.0t^2)i + (5.0j) - (6.0t)k.
Taking the second derivative of r(t) with respect to time t, we get a(t) = 6.0i - 6.0k.
Setting a(t) equal to 0 and solving for t, we get:
6.0i - 6.0k = 0
6.0i = 6.0k
i = k
Therefore, near the time when the instantaneous acceleration is equal to 0, t = 1.0 s.