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Given the function f(x)=x²−6x a. Evaluate f(2) f(2)= b. Solve f(x)=7. Note: If there is more than one solution then enter the solutions write 2;3 in the answer. x=

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Answer:the solutions to f(x) = 7 are x = 7 and x = -1.

Step-by-step explanation:a. To evaluate f(2), we substitute x = 2 into the function f(x) = x² - 6x:

f(2) = (2)² - 6(2)

= 4 - 12

= -8

Therefore, f(2) = -8.

b. To solve f(x) = 7, we set the equation equal to 7 and solve for x:

x² - 6x = 7

To solve this quadratic equation, we bring all terms to one side:

x² - 6x - 7 = 0

Now, we can factor or use the quadratic formula to solve for x. Factoring this equation might not be possible, so we'll use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In our case, a = 1, b = -6, and c = -7. Substituting these values into the formula, we get:

x = (-(-6) ± √((-6)² - 4(1)(-7))) / (2(1))

x = (6 ± √(36 + 28)) / 2

x = (6 ± √64) / 2

x = (6 ± 8) / 2

Simplifying further, we have two possible solutions:

x₁ = (6 + 8) / 2 = 14 / 2 = 7

x₂ = (6 - 8) / 2 = -2 / 2 = -1

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