Question

The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and W is the width of the rectangle. Can the perimeter of the rectangle be 60 units when its width is 11 units and its length is 24 units?

Answer 1

(A) No, if the length is 24 units and the width is 11 units, the perimeter would be P = 48 + 22 = 70 units, not 60.

Explanation:

Using the given formula:

P = 2L + 2W

as well as the given lengths:

• L = 24
• W = 11

we can find the rectangle's perimeter by plugging the given dimensions into the perimeter formula:

P = 2(24) + 2(11)

P = 48 + 22

P = 70

So, the answer is option (A):

No, if the length is 24 units and the width is 11 units, the perimeter would be P = 48 + 22 = 70 units, not 60.