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27 votes
Hey there Ms or Mr could you please help me out with this problem?just so you know, this is Pythagorean theorem & Simplifying Radicals My recent tutor said that this is the answer of course no I don't have any doubts I just want to know if this is correct.

Hey there Ms or Mr could you please help me out with this problem?just so you know-example-1
User Gekrish
by
3.0k points

1 Answer

14 votes
14 votes

When we have a radical, we can simplify it by the rule:


\sqrt[]{ab}=\sqrt[]{a}\sqrt[]{b}

So, we have to break down 500 into simpler radicals until we have a radical that can't be broken down. Let's simplify Root(500).


\sqrt[]{500}=\sqrt[]{50}\sqrt[]{10}

Now, we can break down Root(50) further.


\begin{gathered} \sqrt[]{50}\sqrt[]{10} \\ =\sqrt[]{25}\sqrt[]{2}\sqrt[]{10} \end{gathered}

Now, let's break down Root(10) also, thus we have:


\begin{gathered} \sqrt[]{25}\sqrt[]{2}\sqrt[]{10} \\ =\sqrt[]{25}\sqrt[]{2}\sqrt[]{5}\sqrt[]{2} \end{gathered}

We can see:

• Root(25) is 5

,

• Also Root(2)*Root(2) is 2 by using the rule:


\sqrt[]{a}\sqrt[]{a}=a

Thus, we finally have:


\begin{gathered} \sqrt[]{25}\sqrt[]{2}\sqrt[]{5}\sqrt[]{2} \\ =5(2)\sqrt[]{5} \\ =10\sqrt[]{5} \end{gathered}

User Jaytiger
by
2.9k points
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