Question

5/8 (X-1/2)=10
what number should both sides be divided by?

Answer 1

Answer: I've been typing ALOT to day lol

Step-by-step explanation:

To solve the equation 5/8 (X-1/2) = 10, we need to isolate the variable X. To do that, we should divide both sides of the equation by the coefficient of X, which is 5/8.

Let's go through the steps:

1. Start with the equation: 5/8 (X-1/2) = 10

2. To cancel out the coefficient of X, we need to divide both sides of the equation by 5/8. This will give us:

(X-1/2) = 10 ÷ (5/8)

3. To simplify the right side of the equation, we can multiply 10 by the reciprocal of 5/8, which is 8/5. This gives us:

(X-1/2) = 10 × (8/5)

4. Multiply 10 by 8/5:

(X-1/2) = 16/1

5. Now, we have:

X - 1/2 = 16/1

6. To isolate X, we need to cancel out the -1/2 on the left side. We can do this by adding 1/2 to both sides of the equation:

X - 1/2 + 1/2 = 16/1 + 1/2

7. Simplify the equation:

X = 16/1 + 1/2

8. To add the fractions, we need a common denominator. The least common denominator for 1 and 2 is 2, so we convert 16/1 to 32/2:

X = 32/2 + 1/2

9. Add the fractions:

X = (32 + 1) / 2

10. Simplify the numerator:

X = 33/2

Therefore, the value of X that satisfies the equation 5/8 (X-1/2) = 10 is X = 33/2.

Answer 2

To solve the equation 5/8 (X-1/2)=10, divide both sides by 5/8 or equivalently multiply both sides by the reciprocal, which is 8/5, to isolate the variable X.

Step-by-step explanation:

The equation given is 5/8 (X-1/2)=10. To isolate 'X', you need to perform operations that will simplify the equation. Firstly, you aim to get rid of the fraction in front of the parentheses. Since we're dealing with a fraction (5/8), we need to do the opposite operation of multiplying by 5/8, which is dividing by 5/8 or equivalently multiplying by its reciprocal, which is 8/5. Therefore, to isolate X, you would divide both sides by 5/8 or multiply both sides by 8/5, to cancel the fraction out. After doing so, the next step will involve dealing with the subtraction of 1/2 inside the parentheses.