Question

In a metal processing plant, Tyrese is testing a new instrument that measures heat transfer and temperature. He cools a \[100.0 \degree \text{C}\], \[32.0 \, \text{g}\] piece of iron by placing it in \[50.0 \, \text{g}\] of water at \[50.0 \degree \text{C}\]. As the iron cools, \[1590 \, \text{J}\] of heat is transferred to the water. Assume no energy is lost from the system. Use \[c = 4{,}190 \, \text{J/kg}\degree \text{C}\] for water. Calculate the final temperature of the water-iron control system.

Answer 1

57.59 degrees Celsius

Step-by-step explanation:

So first let's write out what is given.

For iron we have

Temp initial (Ti)= 100 degrees celsius

mass(m) = 32 g or 0.32 kg

For the water we have

m= 50 g= 0.05 kg

Ti= 50 degrees Celsius

specific heat c = 4190 J/(kg * degrees Celsius)

Now the problem states no energy is lost, which means all heat lost by the iron will be gained by the water.

The problem tells us that the iron lost 1590 J of heat, therefore the water will gain that much heat.

I have attached a picture with the work

Hope this helps