75.2k views
1 vote
The boundary line of graph of 2x-3y<4

User Raffy
by
8.5k points

1 Answer

1 vote

Answer:

Explanation:

The boundary line of the inequality 2x - 3y < 4 can be found by first converting it to an equation and then graphing it. To convert it to an equation, you set it equal to 4:

2x - 3y = 4

Now, to graph this line, you can find its x- and y-intercepts.

X-intercept:

Set y to 0 and solve for x:

2x - 3(0) = 4

2x = 4

x = 4/2

x = 2

So, the x-intercept is (2, 0).

Y-intercept:

Set x to 0 and solve for y:

2(0) - 3y = 4

-3y = 4

y = 4/(-3)

y ≈ -1.33 (rounded to two decimal places)

So, the y-intercept is (0, -1.33) or approximately (0, -4/3).

Now, you can plot these two points and draw a straight line through them. This line represents the boundary of the inequality 2x - 3y < 4.

The line will have a positive slope, passing through the points (2, 0) and (0, -1.33), and it will be shaded below this line to represent the region that satisfies the inequality 2x - 3y < 4.

User Jamesmortensen
by
8.0k points